h=int(input())
a=h
for x in range(9):
    h+=a*((1/2)**x)
print(f'{h:.6g}\n{a*((1/2)**10):.6g}')

#include <stdio.h>
int main()
{
    double h=0;
    scanf("%lf",&h);
    double sum=h;

    for (int num=1;num<10;num++){
        sum+=h;
        h/=2;
    }
        h/=2;
    printf("%.6g\n%.6g",sum,h);

    return 0;
}

#include <stdio.h>

int main()
{
    double n, sum = 0;
    scanf("%lf", &n);

    for (int i = 0; i < 10; i++)
    {
        sum += n;
        n /= 2.0;
        if (i != 9)
        {
            sum += n;
        }
    }

    printf("%.6g\n%.6g",sum, n);

    return 0;
}